Board Thread:Wiki discussions and announcements/@comment-26053782-20150129202217/@comment-24055932-20150219134754

Given that my formula doesn't work, I'm now looking if the total amplification factor for 2 given amps even stays constant, I'm not so sure anymore. To use the data from this discussion:

1. AD, Amps: 1.06 & 1.05 ,

.1 250 raw bonus AD, 286 amped bonus AD. Ratio is 286/250 ≈ 1.144 .2 545 raw bonus AD, 617 amped bonus AD. Ratio is 617/545 ≈ 1.132 (with amp factor 1.144 the amped bonus would have been 545*1.144= 623.48 ~ 6 diff ==> no rounding error) .3 125.35 raw bonus AD, 146 amped bonus AD. Ratio is 146/125.35 ≈ 1.165 [Spectator data, level 13 Riven with 82 Base_AD; precision of the quotient is 0.008]

2. AP, Amps: 1.3 & 1.06 ,

.1 480 raw AP, 674 amped AP. Ratio is 674/480 ≈ 1.404 [Missing data]

Current assumption: Yet to start again at 0, as the total amplification factor is a function of the value (raw AP/AD).

But honestly, if this is the case, we're pretty much done. At best, if somebody takes the time to calculate the quotient for all values from 0 to 1000 we might be able to find a substitution formula that plots all given points with minimal error... but looking at the the progression given by the 3 dots I've I've calculated, it looks like a function of the class (1/(ax+b)), and I know no other way to fit those than a few numerical algorythms that would take quite some time to calculate...