Talk:Lee Sin/@comment-24496127-20140716033238/@comment-6281696-20140718231153

To put it very simple:

If Y wins everything with 60% and X wins everything with 90%, except from Z & Y. Against Z it always loses against Y it losses 40% of the time. On average X's winrate is much much much higher (it limits on 90% basicly, depending on how many other options there are).

I pick X, opponent picks Z. I pick Z, opponent picks Y. I pick Y, opponent is forced to pick an inferiour pick regardless of what he goes with.

Y is gametheoreticly just the best option, even if his overall winrate is up to 30%!!! less than X's winrate.

That's the basic maths behind what U N is argueing.