Talk:Runes Reforged/@comment-27948271-20171110103204/@comment-33612286-20171110163249

To illustrate why there are only (3*9) = 27 possible combinations within the secondary tree I will manually count out all the possible unique combinations.

A1 A2 A3

B1 B2 B3

C1 C2 C3

The matrix above simulates the three sets of three runes each possible in the secondary tree.

Runes A1, A2, A3 can each form 6 pairings with either the runes from set B or set C.

This gives us 6 * 3 = 18 additional combinations.

Since, the set of runes "A" has already been combined with B and C, runes B1, B2, B3 can only form pairings with the runes from set C to generate any additional unique combinations.

There can be three pairings per rune B formed in this way. This leads us to have and additional 3 * 3 = 9 combinations.

Finally, since the pairings between A and C and B and C have been completed, no additional unique pairings from set C can be made.

Adding the number of ways we can create unique combinations of 2, we have 18 + 9 = 27.